What is the foci (x^2)/(36)+(y^2)/(100)=1 ?

The foci (x^2)/(36)+(y^2)/(100)=1 is (0,8),(0,-8)

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foci (x^2)/(36)+(y^2)/(100)=1

foci

\frac{x ^{2}}{36} + \frac{y ^{2}}{100} = 1

(0, 8), (0, - 8)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{36} + \frac{y ^{2}}{100} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 10, a = 6

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1 0^{2} - 6^{2} : 8

(0, 0 + 8), (0, 0 - 8)

Refine

(0, 8), (0, - 8)

f (x) = - x^{2} - 2 x + 3

x^{2} + y^{2} = 4

9 y^{2} - 16 x^{2} - 256 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{36} = 1

- x^{2} - 6 x + y - 8 = 0

What is the foci (x^2)/(36)+(y^2)/(100)=1 ?
The foci (x^2)/(36)+(y^2)/(100)=1 is (0,8),(0,-8)