{
"query": {
"display": "vertices $$y=x^{2}+2x-3$$",
"symbolab_question": "CONIC#vertices y=x^{2}+2x-3"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "vertices",
"default": "\\mathrm{Minimum}\\:(-1,-4)",
"meta": {
"showVerify": true
}
},
"methods": [
{
"method": "Find vertex using polynomial form",
"query": {
"display": "vertex quadratic $$y=x^{2}+2x-3$$",
"symbolab_question": "vertexquadratic y=x^{2}+2x-3"
}
},
{
"method": "Find vertex using parabola form",
"query": {
"display": "vertex parabola $$y=x^{2}+2x-3$$",
"symbolab_question": "vertexparabola y=x^{2}+2x-3"
}
},
{
"method": "Find vertex using vertex form",
"query": {
"display": "vertex form $$y=x^{2}+2x-3$$",
"symbolab_question": "vertexform y=x^{2}+2x-3"
}
},
{
"method": "Find vertex using averaging the zeros",
"query": {
"display": "vertex zeros $$y=x^{2}+2x-3$$",
"symbolab_question": "vertexzeros y=x^{2}+2x-3"
}
}
],
"steps": {
"type": "interim",
"title": "Parabola vertex given $$y=x^{2}+2x-3:{\\quad}$$Minimum $$\\left(-1,\\:-4\\right)$$",
"input": "y=x^{2}+2x-3",
"steps": [
{
"type": "definition",
"title": "Parabola equation in polynomial form",
"text": "The vertex of an up-down facing parabola of the form $$y=ax^2+bx+c\\:$$is $$x_{v}=-\\frac{b}{2a}$$"
},
{
"type": "step",
"primary": "The parabola parameters are:",
"result": "a=1,\\:b=2,\\:c=-3"
},
{
"type": "step",
"primary": "$$x_{v}=-\\frac{b}{2a}$$",
"result": "x_{v}=-\\frac{2}{2\\cdot\\:1}"
},
{
"type": "step",
"primary": "Simplify",
"result": "x_{v}=-1"
},
{
"type": "interim",
"title": "Plug in $$x_{v}=-1\\:$$to find the $$y_{v}\\:$$value",
"input": "y_{v}=\\left(-1\\right)^{2}+2\\left(-1\\right)-3",
"result": "y_{v}=-4",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\left(-1\\right)^{2}+2\\left(-1\\right)-3:{\\quad}-4$$",
"input": "\\left(-1\\right)^{2}+2\\left(-1\\right)-3",
"result": "y_{v}=-4",
"steps": [
{
"type": "step",
"primary": "Remove parentheses: $$\\left(-a\\right)=-a$$",
"result": "=\\left(-1\\right)^{2}-2\\cdot\\:1-3"
},
{
"type": "interim",
"title": "$$\\left(-1\\right)^{2}=1$$",
"input": "\\left(-1\\right)^{2}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(-a\\right)^{n}=a^{n},\\:$$if $$n$$ is even",
"secondary": [
"$$\\left(-1\\right)^{2}=1^{2}$$"
],
"result": "=1^{2}"
},
{
"type": "step",
"primary": "Apply rule $$1^{a}=1$$",
"result": "=1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s78E1FVQW6YvXK7raPRxih+c0ag8T1MwTer44+aCS/ZFAdx7pcd1x/bAWpIL8hAintf05A2GsVmPba4FjoW22b4iKyMg44e9p5G7GRfJ2en9g="
}
},
{
"type": "interim",
"title": "$$2\\cdot\\:1=2$$",
"input": "2\\cdot\\:1",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:1=2$$",
"result": "=2"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7+PAYxXmLR4nDEBHt2jGqsN13jtrSFDx+UNsawjlOjV3jAewWnbvHwHHNJ9dhy4+WsiFkFLY2UCqxUg31WjmL6HgMxnm5w+rT3GGDPdan9jw="
}
},
{
"type": "step",
"result": "=1-2-3"
},
{
"type": "step",
"primary": "Subtract the numbers: $$1-2-3=-4$$",
"result": "=-4"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7zzuoR3/JnHaL2vl58S3gaDrfVeRXG9KjJU5mgumU/Bl5tMpJTBBccUWkSyvMe1SpIvsJv/VpmBmOllN+wMnDXXKF3u2OIb4bFA3EO8aRlSXM5rdwdO/6wbzT4FNnvlhePMuJclWpVka0IO+Hi/jfqQ=="
}
}
],
"meta": {
"interimType": "Plug In Value 2Eq"
}
},
{
"type": "step",
"primary": "Therefore the parabola vertex is",
"result": "\\left(-1,\\:-4\\right)"
},
{
"type": "step",
"primary": "If $$a<0,\\:$$then the vertex is a maximum value<br/>If $$a>0,\\:$$then the vertex is a minimum value<br/>$$a=1$$",
"result": "\\mathrm{Minimum}\\:\\left(-1,\\:-4\\right)"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\frac{(x-(-1))^{2}}{4\\frac{1}{4}}-4",
"displayFormula": "4\\frac{1}{4}(y-(-4))=(x-(-1))^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=-\\frac{17}{4}",
"displayFormula": "y=-\\frac{17}{4}",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(-1,-4)",
"(-1,-\\frac{15}{4})"
],
"pointsDecimal": [
{
"fst": -1,
"snd": -4
},
{
"fst": -1,
"snd": -3.75
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4\\cdot \\frac{1}{4}(y-(-4))=(x-(-1))^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -4.414285714285715,
"xMax": 2.7285714285714286,
"yMin": -5.714285714285714,
"yMax": 1.4285714285714288
}
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
vertices
Solution
Solution steps
The parabola parameters are:
Simplify
Plug in to find the value
Therefore the parabola vertex is
If then the vertex is a maximum value
If then the vertex is a minimum value
Graph
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Frequently Asked Questions (FAQ)
What is the vertices y=x^2+2x-3 ?
The vertices y=x^2+2x-3 is Minimum (-1,-4)