{
"query": {
"display": "vertices $$2x^{2}$$",
"symbolab_question": "CONIC#vertices 2x^{2}"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "vertices",
"default": "\\mathrm{Minimum}\\:(0,0)",
"meta": {
"showVerify": true
}
},
"methods": [
{
"method": "Find vertex using polynomial form",
"query": {
"display": "vertex quadratic $$y=2x^{2}$$",
"symbolab_question": "vertexquadratic y=2x^{2}"
}
},
{
"method": "Find vertex using parabola form",
"query": {
"display": "vertex parabola $$y=2x^{2}$$",
"symbolab_question": "vertexparabola y=2x^{2}"
}
},
{
"method": "Find vertex using vertex form",
"query": {
"display": "vertex form $$y=2x^{2}$$",
"symbolab_question": "vertexform y=2x^{2}"
}
},
{
"method": "Find vertex using averaging the zeros",
"query": {
"display": "vertex zeros $$y=2x^{2}$$",
"symbolab_question": "vertexzeros y=2x^{2}"
}
}
],
"steps": {
"type": "interim",
"title": "Parabola vertex given $$y=2x^{2}:{\\quad}$$Minimum $$\\left(0,\\:0\\right)$$",
"input": "y=2x^{2}",
"steps": [
{
"type": "definition",
"title": "Parabola equation in polynomial form",
"text": "The vertex of an up-down facing parabola of the form $$y=ax^2+bx+c\\:$$is $$x_{v}=-\\frac{b}{2a}$$"
},
{
"type": "step",
"primary": "The parabola parameters are:",
"result": "a=2,\\:b=0,\\:c=0"
},
{
"type": "step",
"primary": "$$x_{v}=-\\frac{b}{2a}$$",
"result": "x_{v}=-\\frac{0}{2\\cdot\\:2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "x_{v}=0"
},
{
"type": "interim",
"title": "Plug in $$x_{v}=0\\:$$to find the $$y_{v}\\:$$value",
"input": "y_{v}=2\\cdot\\:0^{2}",
"result": "y_{v}=0",
"steps": [
{
"type": "step",
"primary": "Simplify",
"result": "y_{v}=0"
}
],
"meta": {
"interimType": "Plug In Value 2Eq"
}
},
{
"type": "step",
"primary": "Therefore the parabola vertex is",
"result": "\\left(0,\\:0\\right)"
},
{
"type": "step",
"primary": "If $$a<0,\\:$$then the vertex is a maximum value<br/>If $$a>0,\\:$$then the vertex is a minimum value<br/>$$a=2$$",
"result": "\\mathrm{Minimum}\\:\\left(0,\\:0\\right)"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\frac{x^{2}}{4\\frac{1}{8}}+0",
"displayFormula": "4\\frac{1}{8}y=x^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=-\\frac{1}{8}",
"displayFormula": "y=-\\frac{1}{8}",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(0,0)",
"(0,\\frac{1}{8})"
],
"pointsDecimal": [
{
"fst": 0,
"snd": 0
},
{
"fst": 0,
"snd": 0.125
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4\\cdot \\frac{1}{8}(y)=x^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -1.40625,
"xMax": 1.40625,
"yMin": -1.40625,
"yMax": 1.40625
}
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
vertices
Solution
Solution steps
The parabola parameters are:
Simplify
Plug in to find the value
Therefore the parabola vertex is
If then the vertex is a maximum value
If then the vertex is a minimum value
Graph
Popular Examples
foci 4y^2-25x^2=100foci -9x^2+y^2-72x-153=0vertices f(x)=x^2-2x-15vertices x^2-9y^2=9foci (x^2)/(36)+(y^2)/(100)=1foci
Frequently Asked Questions (FAQ)
What is the vertices 2x^2 ?
The vertices 2x^2 is Minimum (0,0)