What is (x^2)/(25)+(y^2)/(36)=1 ?

The solution to (x^2)/(25)+(y^2)/(36)=1 is Ellipse with (h,k)=(0,0),a=5,b=6

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(x^2)/(25)+(y^2)/(36)=1

\frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

(h, k) = (0, 0), a = 5, b = 6

Solution steps

\frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 6, a = 5

2 x^{2}

4 y^{2} - 25 x^{2} = 100

- 9 x^{2} + y^{2} - 72 x - 153 = 0

f (x) = x^{2} - 2 x - 15

x^{2} - 9 y^{2} = 9

What is (x^2)/(25)+(y^2)/(36)=1 ?
The solution to (x^2)/(25)+(y^2)/(36)=1 is Ellipse with (h,k)=(0,0),a=5,b=6