What is the foci (x+3)^2=8(y-2) ?

The foci (x+3)^2=8(y-2) is (-3,4)

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foci (x+3)^2=8(y-2)

foci

(x + 3)^{2} = 8 (y - 2)

(- 3, 4)

Solution steps

Rewrite

(x + 3)^{2} = 8 (y - 2)

in the standard form:

4 \cdot 2 (y - 2) = (x - (- 3))^{2}

(h, k) = (- 3, 2), p = 2

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 3, 2)

along the y-axis

(- 3, 2 + p)

= (- 3, 2 + 2)

Refine

(- 3, 4)

y = - 3 x^{2} + 30 x - 71

(x - 3)^{2}

y^{2} + 10 y - 12 x + 37 = 0

4 x^{2} - 4 x + 3

- 2 x^{2} + 4 x - 6