What is the foci y^2+8y-12x-20=0 ?

The foci y^2+8y-12x-20=0 is (0,-4)

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foci y^2+8y-12x-20=0

foci

y^{2} + 8 y - 12 x - 20 = 0

(0, - 4)

Solution steps

Rewrite

y^{2} + 8 y - 12 x - 20 = 0

in the standard form

4 \cdot 3 (x - (- 3)) = (y - (- 4))^{2}

(h, k) = (- 3, - 4), p = 3

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(- 3, - 4)

along the x-axis

(- 3 + p, - 4)

= (- 3 + 3, - 4)

Refine

(0, - 4)

- 9 x^{2}

- 2 x^{2} + 12 x - 10

2 y^{2} + 8 y + x + 1 = 0

x^{2} - 4 x - 12

+ 18500 (0.09 - x^{2})