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Popular >

foci y=x^2+4x+3

Solution

foci

y = x^{2} + 4 x + 3

Solution

(- 2, - \frac{3}{4})

Solution steps

Rewrite

y = x^{2} + 4 x + 3

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - (- 2))^{2}

(h, k) = (- 2, - 1), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 2, - 1)

along the y-axis

(- 2, - 1 + p)

= (- 2, - 1 + \frac{1}{4})

Refine

(- 2, - \frac{3}{4})

Popular Examples

foci y=x^2+10x+25 foci

y = x^{2} + 10 x + 25

foci (x+2)^2=8(y-3)foci

(x + 2)^{2} = 8 (y - 3)

foci x^2+2x-12y+37=0 foci

x^{2} + 2 x - 12 y + 37 = 0

foci x^2+4x+6y-2=0 foci

x^{2} + 4 x + 6 y - 2 = 0

foci (x+4)^2=-8(y-3)foci

(x + 4)^{2} = - 8 (y - 3)

Frequently Asked Questions (FAQ)

What is the foci y=x^2+4x+3 ?
The foci y=x^2+4x+3 is (-2,-3/4)