What is the foci y^2-4y-8x+44=0 ?

The foci y^2-4y-8x+44=0 is (7,2)

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foci y^2-4y-8x+44=0

foci

y^{2} - 4 y - 8 x + 44 = 0

(7, 2)

Solution steps

Rewrite

y^{2} - 4 y - 8 x + 44 = 0

in the standard form

4 \cdot 2 (x - 5) = (y - 2)^{2}

(h, k) = (5, 2), p = 2

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(5, 2)

along the x-axis

(5 + p, 2)

= (5 + 2, 2)

Refine

(7, 2)

y^{2} + 8 y - 12 x - 20 = 0

- 9 x^{2}

- 2 x^{2} + 12 x - 10

2 y^{2} + 8 y + x + 1 = 0

x^{2} - 4 x - 12