What is the foci y=5x^2+210x-34775 ?

The foci y=5x^2+210x-34775 is (-21,-739599/20)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y=5x^2+210x-34775

foci

y = 5 x^{2} + 210 x - 34775

(- 21, - \frac{739599}{20})

Solution steps

Rewrite

y = 5 x^{2} + 210 x - 34775

in the standard form

4 \cdot \frac{1}{20} (y - (- 36980)) = (x - (- 21))^{2}

(h, k) = (- 21, - 36980), p = \frac{1}{20}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 21, - 36980)

along the y-axis

(- 21, - 36980 + p)

= (- 21, - 36980 + \frac{1}{20})

Refine

(- 21, - \frac{739599}{20})

y^{2} - x = 0

y^{2} + 28 x = 0

y^{2} + 12 x + 4 y - 32 = 0

y = (5 - x) (2 x - 3)

y + 4 x \leq x^{2} + 2

What is the foci y=5x^2+210x-34775 ?
The foci y=5x^2+210x-34775 is (-21,-739599/20)