en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y^2+28x=0

Solution

foci

y^{2} + 28 x = 0

Solution

(- 7, 0)

Solution steps

Rewrite

y^{2} + 28 x = 0

in the standard form:

4 (- 7) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 7

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- 7), 0)

Refine

(- 7, 0)

Popular Examples

foci y^2+12x+4y-32=0 foci

y^{2} + 12 x + 4 y - 32 = 0

foci y=(5-x)(2x-3)foci

y = (5 - x) (2 x - 3)

foci y+4x<= x^2+2 foci

y + 4 x \leq x^{2} + 2

foci x^2-6x-4y+5=0 foci

x^{2} - 6 x - 4 y + 5 = 0

foci y=6x^2+26x+8 foci

y = 6 x^{2} + 26 x + 8

Frequently Asked Questions (FAQ)

What is the foci y^2+28x=0 ?
The foci y^2+28x=0 is (-7,0)