What is the foci y=(5-x)(2x-3) ?

The foci y=(5-x)(2x-3) is (13/4 ,6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci y=(5-x)(2x-3)

foci

y = (5 - x) (2 x - 3)

(\frac{13}{4}, 6)

Solution steps

Rewrite

y = (5 - x) (2 x - 3)

in the standard form

4 (- \frac{1}{8}) (y - \frac{49}{8}) = (x - \frac{13}{4})^{2}

(h, k) = (\frac{13}{4}, \frac{49}{8}), p = - \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{13}{4}, \frac{49}{8})

along the y-axis

(\frac{13}{4}, \frac{49}{8} + p)

= (\frac{13}{4}, \frac{49}{8} + (- \frac{1}{8}))

Refine

(\frac{13}{4}, 6)

y + 4 x \leq x^{2} + 2

x^{2} - 6 x - 4 y + 5 = 0

y = 6 x^{2} + 26 x + 8

y = x^{2} + 7 x + 10

y = (2 x - 1) (4 x - 1)