What is the foci y=2x(x-9)-(x-9) ?

The foci y=2x(x-9)-(x-9) is (19/4 ,-36)

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foci y=2x(x-9)-(x-9)

foci

y = 2 x (x - 9) - (x - 9)

(\frac{19}{4}, - 36)

Solution steps

Rewrite

y = 2 x (x - 9) - (x - 9)

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{289}{8})) = (x - \frac{19}{4})^{2}

(h, k) = (\frac{19}{4}, - \frac{289}{8}), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{19}{4}, - \frac{289}{8})

along the y-axis

(\frac{19}{4}, - \frac{289}{8} + p)

= (\frac{19}{4}, - \frac{289}{8} + \frac{1}{8})

Refine

(\frac{19}{4}, - 36)

- 0.0000848 x^{2} - 0.006005 x + 1.004

x^{2} + 16 y = 0

y = 4 x^{2} - 9

y = 160 x - 16 x^{2}

(1060 - x)^{2} + x^{2}