What is the foci-0.0000848x^2-0.006005x+1.004 ?

The foci-0.0000848x^2-0.006005x+1.004 is (-35.40683…,-2948.11320…)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci-0.0000848x^2-0.006005x+1.004

foci

- 0.0000848 x^{2} - 0.006005 x + 1.004

(- 35.40683 \dots, - 2948.11320 \dots)

Solution steps

Rewrite

y = - 0.0000848 x^{2} - 0.006005 x + 1.004

in the standard form

4 (- 2948.11320 \dots) (y - 0) = (x - (- \frac{0.006005}{0.0001696}))^{2}

(h, k) = (- \frac{0.006005}{0.0001696}, 0), p = - 2948.11320 \dots

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{0.006005}{0.0001696}, 0)

along the y-axis

(- \frac{0.006005}{0.0001696}, 0 + p)

= (- \frac{0.006005}{0.0001696}, 0 + (- 2948.11320 \dots))

Refine

(- 35.40683 \dots, - 2948.11320 \dots)

x^{2} + 16 y = 0

y = 4 x^{2} - 9

y = 160 x - 16 x^{2}

(1060 - x)^{2} + x^{2}

y^{2} + 8 x = 0

What is the foci-0.0000848x^2-0.006005x+1.004 ?
The foci-0.0000848x^2-0.006005x+1.004 is (-35.40683…,-2948.11320…)