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Popular >

foci x^2+16y=0

Solution

foci

x^{2} + 16 y = 0

Solution

(0, - 4)

Solution steps

Rewrite

x^{2} + 16 y = 0

in the standard form:

4 (- 4) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - 4

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + (- 4))

Refine

(0, - 4)

Popular Examples

foci y=4x^2-9 foci

y = 4 x^{2} - 9

foci y=160x-16x^2 foci

y = 160 x - 16 x^{2}

foci (1060-x)^2+x^2 foci

(1060 - x)^{2} + x^{2}

foci y^2+8x=0 foci

y^{2} + 8 x = 0

foci 9x^2+4y=1 foci

9 x^{2} + 4 y = 1

Frequently Asked Questions (FAQ)

What is the foci x^2+16y=0 ?
The foci x^2+16y=0 is (0,-4)