What is the foci x=(y+3)^2 ?

The foci x=(y+3)^2 is (1/4 ,-3)

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foci x=(y+3)^2

foci

x = (y + 3)^{2}

(\frac{1}{4}, - 3)

Solution steps

Rewrite

x = (y + 3)^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - (- 3))^{2}

(h, k) = (0, - 3), p = \frac{1}{4}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, - 3)

along the x-axis

(0 + p, - 3)

= (0 + \frac{1}{4}, - 3)

Refine

(\frac{1}{4}, - 3)

x^{2} - 6 x + 5 y = 34

y = 2 x (x - 9) - (x - 9)

- 0.0000848 x^{2} - 0.006005 x + 1.004

x^{2} + 16 y = 0

y = 4 x^{2} - 9