What is the asymptotes of (x^2)/(64)-(y^2)/(36)=1 ?

The asymptotes of (x^2)/(64)-(y^2)/(36)=1 is y=(3x)/4 ,\quad y=-(3x)/4

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asymptotes of (x^2)/(64)-(y^2)/(36)=1

asymptotes

\frac{x ^{2}}{64} - \frac{y ^{2}}{36} = 1

y = \frac{3 x}{4}, y = - \frac{3 x}{4}

Solution steps

y = \pm \frac{b}{a} (x - h) + k

Calculate Hyperbola properties

\frac{x ^{2}}{64} - \frac{y ^{2}}{36} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 8, b = 6

y = \frac{6}{8} (x - 0) + 0, y = - \frac{6}{8} (x - 0) + 0

Refine

y = \frac{3 x}{4}, y = - \frac{3 x}{4}

x^{2} + y^{2} - 6 x + 2 y + 9 = 0

4 x^{2} + y^{2} = 16

y = x^{2} - 24 x - 12

x = 4 y^{2}

\frac{x ^{2}}{36} + \frac{y ^{2}}{49} = 1

What is the asymptotes of (x^2)/(64)-(y^2)/(36)=1 ?
The asymptotes of (x^2)/(64)-(y^2)/(36)=1 is y=(3x)/4 ,\quad y=-(3x)/4