What is the f(x)=-0.99968(x^2-2.5x-0.23808) ?

The f(x)=-0.99968(x^2-2.5x-0.23808) is

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f(x)=-0.99968(x^2-2.5x-0.23808)

f (x) = - 0.99968 (x^{2} - 2.5 x - 0.23808)

Domain : - \infty < x < \infty

Range : f (x) \leq 1.80000 \dots

X Intercepts : (- \frac{- 2.4992 + 7.19771 \dots}{1.99936}, 0), (\frac{2.4992 + 7.19771 \dots}{1.99936}, 0), Y Intercepts : (0, 0.2380038144)

Vertex : Maximum (1.25, 1.80000 \dots)

Inverse : - \frac{- 2.4992 + - 3.99872 x + 7.19771 \dots}{1.99936}, - \frac{- 2.4992 - - 3.99872 x + 7.19771 \dots}{1.99936}

Solution steps

Domain of

- 0.99968 (x^{2} - 2.5 x - 0.23808) : - \infty < x < \infty

Range of

- 0.99968 (x^{2} - 2.5 x - 0.23808) : f (x) \leq 1.80000 \dots

Axis interception points of

- 0.99968 (x^{2} - 2.5 x - 0.23808) :

X Intercepts

: (- \frac{- 2.4992 + 7.19771 \dots}{1.99936}, 0), (\frac{2.4992 + 7.19771 \dots}{1.99936}, 0),

Y Intercepts

: (0, 0.2380038144)

Vertex of

- 0.99968 (x^{2} - 2.5 x - 0.23808) :

Maximum

(1.25, 1.80000 \dots)

Inverse of

- 0.99968 (x^{2} - 2.5 x - 0.23808) : - \frac{- 2.4992 + - 3.99872 x + 7.19771 \dots}{1.99936}, - \frac{- 2.4992 - - 3.99872 x + 7.19771 \dots}{1.99936}

x^{2} + 4^{2} - 14 x + 2 y = - 14

(x - 2)^{(2)} = \frac{( 1 )}{2} (y - 1)

12 X^{2} = - 4 Y

y^{2} - 66 y + 1089 = 4 a x - 4 ah

x^{2} - 8 y - 16 = 0

What is the f(x)=-0.99968(x^2-2.5x-0.23808) ?
The f(x)=-0.99968(x^2-2.5x-0.23808) is