What is y^2-66y+1089=4ax-4ah ?

The solution to y^2-66y+1089=4ax-4ah is Parabola with (h,k)=(4ah,33),p= 1/4

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y^2-66y+1089=4ax-4ah

y^{2} - 66 y + 1089 = 4 a x - 4 ah

(h, k) = (4 ah, 33), p = \frac{1}{4}

Solution steps

y^{2} - 66 y + 1089 = 4 a x - 4 ah

Rewrite

y^{2} - 66 y + 1089 = 4 a x - 4 ah

in the standard form

4 \cdot \frac{1}{4} (x - 4 ah) = (y - 33)^{2}

Therefore parabola properties are:

(h, k) = (4 ah, 33), p = \frac{1}{4}

x^{2} - 8 y - 16 = 0

x^{2} + y = 50

y = \frac{- 2 x}{y}

3 r^{2} = 12 t - 15

y^{2} - 2 y + 1 - 12 x + 7 - 1 = 0

What is y^2-66y+1089=4ax-4ah ?
The solution to y^2-66y+1089=4ax-4ah is Parabola with (h,k)=(4ah,33),p= 1/4