What is (x-2)^{(2)}=((1))/2 (y-1) ?

The solution to (x-2)^{(2)}=((1))/2 (y-1) is Parabola with (h,k)=(2,1),p= 1/8

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(x-2)^{(2)}=((1))/2 (y-1)

(x - 2)^{(2)} = \frac{( 1 )}{2} (y - 1)

(h, k) = (2, 1), p = \frac{1}{8}

Solution steps

(x - 2)^{2} = \frac{1}{2} (y - 1)

Rewrite

(x - 2)^{2} = \frac{1}{2} (y - 1)

in the standard form:

4 \cdot \frac{1}{8} (y - 1) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 1), p = \frac{1}{8}

12 X^{2} = - 4 Y

y^{2} - 66 y + 1089 = 4 a x - 4 ah

x^{2} - 8 y - 16 = 0

x^{2} + y = 50

y = \frac{- 2 x}{y}

What is (x-2)^{(2)}=((1))/2 (y-1) ?
The solution to (x-2)^{(2)}=((1))/2 (y-1) is Parabola with (h,k)=(2,1),p= 1/8