What is x^2+20x+y^2+16y=-20 ?

The solution to x^2+20x+y^2+16y=-20 is Circle with (a,b)=(-10,-8),r=12

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x^2+20x+y^2+16y=-20

x^{2} + 20 x + y^{2} + 16 y = - 20

(a, b) = (- 10, - 8), r = 12

Solution steps

x^{2} + 20 x + y^{2} + 16 y = - 20

Rewrite

x^{2} + 20 x + y^{2} + 16 y = - 20

in the form of the standard circle equation

(x - (- 10))^{2} + (y - (- 8))^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (- 10, - 8), r = 12

\frac{x ^{2}}{64} - \frac{y ^{2}}{36} = 1

x^{2} + y^{2} - 6 x + 2 y + 9 = 0

4 x^{2} + y^{2} = 16

y = x^{2} - 24 x - 12

x = 4 y^{2}

What is x^2+20x+y^2+16y=-20 ?
The solution to x^2+20x+y^2+16y=-20 is Circle with (a,b)=(-10,-8),r=12