What is x^2+20x+y^2+16y=-20 ?

The solution to x^2+20x+y^2+16y=-20 is Circle with (a,b)=(-10,-8),r=12

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x^2+20x+y^2+16y=-20

x^{2} + 20 x + y^{2} + 16 y = - 20

(a, b) = (- 10, - 8), r = 12

Solution steps

x^{2} + 20 x + y^{2} + 16 y = - 20

Rewrite

x^{2} + 20 x + y^{2} + 16 y = - 20

in the form of the standard circle equation

(x - (- 10))^{2} + (y - (- 8))^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (- 10, - 8), r = 12

What is x^2+20x+y^2+16y=-20 ?
The solution to x^2+20x+y^2+16y=-20 is Circle with (a,b)=(-10,-8),r=12