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Popular >

foci 16x^2+y^2=16

Solution

foci

16 x^{2} + y^{2} = 16

Solution

(0, 15), (0, - 15)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

16 x^{2} + y^{2} = 16 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 4^{2} - 1^{2} : 15

(0, 0 + 15), (0, 0 - 15)

Refine

(0, 15), (0, - 15)

Popular Examples

vertices f(x)=x^2-2 vertices

f (x) = x^{2} - 2

x^{2} + y^{2} - 9 = 0

foci y^2=20x foci

y^{2} = 20 x

(x^2)/(49)+(y^2)/(16)=1

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

((y-6)^2)/(64)-((x-8)^2)/(36)=1

\frac{( y - 6 ) ^{2}}{64} - \frac{( x - 8 ) ^{2}}{36} = 1

Frequently Asked Questions (FAQ)

What is the foci 16x^2+y^2=16 ?
The foci 16x^2+y^2=16 is (0,sqrt(15)),(0,-sqrt(15))