What is x^2+y^2-9=0 ?

The solution to x^2+y^2-9=0 is Circle with (a,b)=(0,0),r=3

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x^2+y^2-9=0

x^{2} + y^{2} - 9 = 0

(a, b) = (0, 0), r = 3

Solution steps

x^{2} + y^{2} - 9 = 0

Rewrite

x^{2} + y^{2} - 9 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 3

y^{2} = 20 x

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

\frac{( y - 6 ) ^{2}}{64} - \frac{( x - 8 ) ^{2}}{36} = 1

9 x^{2} - 9 y^{2} + 18 x + 36 y = 63

f (x) = x^{2} + 8 x + 12

What is x^2+y^2-9=0 ?
The solution to x^2+y^2-9=0 is Circle with (a,b)=(0,0),r=3