What is ((y-6)^2)/(64)-((x-8)^2)/(36)=1 ?

The solution to ((y-6)^2)/(64)-((x-8)^2)/(36)=1 is Hyperbola with (h,k)=(8,6),a=8,b=6

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((y-6)^2)/(64)-((x-8)^2)/(36)=1

\frac{( y - 6 ) ^{2}}{64} - \frac{( x - 8 ) ^{2}}{36} = 1

(h, k) = (8, 6), a = 8, b = 6

Solution steps

\frac{( y - 6 ) ^{2}}{64} - \frac{( x - 8 ) ^{2}}{36} = 1

Rewrite

\frac{( y - 6 ) ^{2}}{64} - \frac{( x - 8 ) ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( y - 6 ) ^{2}}{8 ^{2}} - \frac{( x - 8 ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (8, 6), a = 8, b = 6

9 x^{2} - 9 y^{2} + 18 x + 36 y = 63

f (x) = x^{2} + 8 x + 12

\frac{x ^{2}}{16} - \frac{y ^{2}}{25} = 1

x^{2} = 28 y

x = - y^{2}

What is ((y-6)^2)/(64)-((x-8)^2)/(36)=1 ?
The solution to ((y-6)^2)/(64)-((x-8)^2)/(36)=1 is Hyperbola with (h,k)=(8,6),a=8,b=6