What is (x^2)/(16)-(y^2)/(25)=1 ?

The solution to (x^2)/(16)-(y^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=4,b=5

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(x^2)/(16)-(y^2)/(25)=1

\frac{x ^{2}}{16} - \frac{y ^{2}}{25} = 1

(h, k) = (0, 0), a = 4, b = 5

Solution steps

\frac{x ^{2}}{16} - \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{16} - \frac{y ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 5

x^{2} = 28 y

x = - y^{2}

9 y^{2} - 16 x^{2} = 81

x = y^{2} - 2 y

y^{2} = - \frac{4}{5} (x - 2)

What is (x^2)/(16)-(y^2)/(25)=1 ?
The solution to (x^2)/(16)-(y^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=4,b=5