What is (x^2}{49}+\frac{y^2)/9 =1 ?

The solution to (x^2}{49}+\frac{y^2)/9 =1 is Ellipse with (h,k)=(0,0),a=7,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2}{49}+\frac{y^2)/9 =1

\frac{x ^{2}}{49} + \frac{y ^{2}}{9} = 1

(h, k) = (0, 0), a = 7, b = 3

Solution steps

\frac{x ^{2}}{49} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{49} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 7, b = 3

y^{2} - x^{2} = 1

x^{2} + 4 y^{2} - 6 x + 20 y - 2 = 0

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

\frac{( x - 5 ) ^{2}}{12} - \frac{( y + 6 ) ^{2}}{17} = 1

- 36 y = x^{2}

What is (x^2}{49}+\frac{y^2)/9 =1 ?
The solution to (x^2}{49}+\frac{y^2)/9 =1 is Ellipse with (h,k)=(0,0),a=7,b=3