What is the eccentricity (x^2)/(25)+(y^2)/(16)=1 ?

The eccentricity (x^2)/(25)+(y^2)/(16)=1 is 3/5

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eccentricity (x^2)/(25)+(y^2)/(16)=1

eccentricity

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

\frac{3}{5}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 5, b = 4

= \frac{5 ^{2} - 4 ^{2}}{5}

\frac{5 ^{2} - 4 ^{2}}{5} = \frac{3}{5}

= \frac{3}{5}

\frac{( x - 5 ) ^{2}}{12} - \frac{( y + 6 ) ^{2}}{17} = 1

- 36 y = x^{2}

5 x^{2} + 7 y^{2} = 35

\frac{( x + 3 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{9} = 1

16 x^{2} - 96 x + 144 + 25 y^{2} = 400

What is the eccentricity (x^2)/(25)+(y^2)/(16)=1 ?
The eccentricity (x^2)/(25)+(y^2)/(16)=1 is 3/5