What is ((x-5)^2)/(12)-((y+6)^2)/(17)=1 ?

The solution to ((x-5)^2)/(12)-((y+6)^2)/(17)=1 is Hyperbola with (h,k)=(5,-6),a=2sqrt(3),b=sqrt(17)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

((x-5)^2)/(12)-((y+6)^2)/(17)=1

\frac{( x - 5 ) ^{2}}{12} - \frac{( y + 6 ) ^{2}}{17} = 1

(h, k) = (5, - 6), a = 23, b = 17

Solution steps

\frac{( x - 5 ) ^{2}}{12} - \frac{( y + 6 ) ^{2}}{17} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{12} - \frac{( y + 6 ) ^{2}}{17} = 1

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{( 2 3 ) ^{2}} - \frac{( y - ( - 6 ) ) ^{2}}{( 17 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, - 6), a = 23, b = 17

What is ((x-5)^2)/(12)-((y+6)^2)/(17)=1 ?
The solution to ((x-5)^2)/(12)-((y+6)^2)/(17)=1 is Hyperbola with (h,k)=(5,-6),a=2sqrt(3),b=sqrt(17)