What is the foci (x^2)/9-(y^2)/4 =1 ?

The foci (x^2)/9-(y^2)/4 =1 is (sqrt(13),0),(-sqrt(13),0)

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foci (x^2)/9-(y^2)/4 =1

foci

\frac{x ^{2}}{9} - \frac{y ^{2}}{4} = 1

(13, 0), (- 13, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{9} - \frac{y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + 2^{2} : 13

(0 + 13, 0), (0 - 13, 0)

Refine

(13, 0), (- 13, 0)

x + y^{2} = 4

y^{2} = - 28 x

\frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

x = y^{2} - 2

y^{2} - 12 y + 4 x + 4 = 0

What is the foci (x^2)/9-(y^2)/4 =1 ?
The foci (x^2)/9-(y^2)/4 =1 is (sqrt(13),0),(-sqrt(13),0)