Solution

vertices

Solution

Solution steps
Calculate Hyperbola properties
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Popular Examples

foci 2x^2+7y^2=1449y^2-x^2=49foci 9x^2+25y^2=225(y^2)/9-(x^2)/(16)=1vertices f(x)=-x^2-4x-3

Frequently Asked Questions (FAQ)

  • What is the vertices (y^2)/9-(x^2)/(16)=1 ?

    The vertices (y^2)/9-(x^2)/(16)=1 is (0,3),(0,-3)