What is (y^2)/9-(x^2)/(16)=1 ?

The solution to (y^2)/9-(x^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=3,b=4

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(y^2)/9-(x^2)/(16)=1

\frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1

(h, k) = (0, 0), a = 3, b = 4

Solution steps

\frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1

Rewrite

\frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{3 ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 4

f (x) = - x^{2} - 4 x - 3

x^{2} + y^{2} - 16 = 0

\frac{y ^{2}}{25} - \frac{x ^{2}}{4} = 1

\frac{y ^{2}}{16} - \frac{x ^{2}}{25} = 1

x^{2} = - 16 y

What is (y^2)/9-(x^2)/(16)=1 ?
The solution to (y^2)/9-(x^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=3,b=4