What is the foci y^2-x^2= 9/25 ?

The foci y^2-x^2= 9/25 is (0,(3sqrt(2))/5),(0,-(3sqrt(2))/5)

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foci y^2-x^2= 9/25

foci

y^{2} - x^{2} = \frac{9}{25}

(0, \frac{3 2}{5}), (0, - \frac{3 2}{5})

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

y^{2} - x^{2} = \frac{9}{25} :

Up-down Hyperbola with

(h, k) = (0, 0), a = \frac{3}{5}, b = \frac{3}{5}

(0, 0 + c), (0, 0 - c)

Compute

c :

c = (\frac{3}{5})^{2} + (\frac{3}{5})^{2} : \frac{3 2}{5}

(0, 0 + \frac{3 2}{5}), (0, 0 - \frac{3 2}{5})

Refine

(0, \frac{3 2}{5}), (0, - \frac{3 2}{5})

\frac{y ^{2}}{25} - \frac{x ^{2}}{11} = 1

\frac{( y ) ^{2}}{121} - \frac{( x ) ^{2}}{81} = 1

8 x^{2} - 3 y^{2} = 24

\frac{( y ) ^{2}}{40} - \frac{( x ) ^{2}}{81} = 1

+ 9 x^{2} - 16 y^{2} = 144

What is the foci y^2-x^2= 9/25 ?
The foci y^2-x^2= 9/25 is (0,(3sqrt(2))/5),(0,-(3sqrt(2))/5)