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foci
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Calculate Hyperbola properties
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foci (y^2)/(25)-(x^2)/(11)=1foci ((y)^2)/(121)-((x)^2)/(81)=1foci 8x^2-3y^2=24foci ((y)^2)/(40)-((x)^2)/(81)=1foci+9x^2-16y^2=144
Frequently Asked Questions (FAQ)
What is the foci y^2-x^2= 9/25 ?
The foci y^2-x^2= 9/25 is (0,(3sqrt(2))/5),(0,-(3sqrt(2))/5)