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foci
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foci 8x^2-3y^2=24foci foci ((y)^2)/(40)-((x)^2)/(81)=1foci foci+9x^2-16y^2=144foci foci (x^2)/4-((y+3)^2)/9 =1foci foci ((x-2)^2)/1-((y+3)^2)/9 =1foci
Frequently Asked Questions (FAQ)
What is the foci ((y)^2)/(121)-((x)^2)/(81)=1 ?
The foci ((y)^2)/(121)-((x)^2)/(81)=1 is (0,sqrt(202)),(0,-sqrt(202))