What is the foci (y^2)/(25)-(x^2)/(11)=1 ?

The foci (y^2)/(25)-(x^2)/(11)=1 is (0,6),(0,-6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

foci (y^2)/(25)-(x^2)/(11)=1

foci

(0, 6), (0, - 6)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{x ^{2}}{11} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 11

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} + 11^{2} : 6

(0, 0 + 6), (0, 0 - 6)

Refine

(0, 6), (0, - 6)

What is the foci (y^2)/(25)-(x^2)/(11)=1 ?
The foci (y^2)/(25)-(x^2)/(11)=1 is (0,6),(0,-6)