What is ((y-11)^2)/(16)-((x+5)^2)/(36)=1 ?

The solution to ((y-11)^2)/(16)-((x+5)^2)/(36)=1 is Hyperbola with (h,k)=(-5,11),a=4,b=6

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((y-11)^2)/(16)-((x+5)^2)/(36)=1

\frac{( y - 11 ) ^{2}}{16} - \frac{( x + 5 ) ^{2}}{36} = 1

(h, k) = (- 5, 11), a = 4, b = 6

Solution steps

\frac{( y - 11 ) ^{2}}{16} - \frac{( x + 5 ) ^{2}}{36} = 1

Rewrite

\frac{( y - 11 ) ^{2}}{16} - \frac{( x + 5 ) ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( y - 11 ) ^{2}}{4 ^{2}} - \frac{( x - ( - 5 ) ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 11), a = 4, b = 6

- 25 x^{2} + y^{2} = 25

(\frac{x}{4})^{2} - \frac{y ^{2}}{2} = 1

a = \frac{2020 - c}{\frac{2021 - a}{c}}

5 y^{2} - 9 x^{2} = 45

x^{2} - 4 y^{2} - 16 y > 1

What is ((y-11)^2)/(16)-((x+5)^2)/(36)=1 ?
The solution to ((y-11)^2)/(16)-((x+5)^2)/(36)=1 is Hyperbola with (h,k)=(-5,11),a=4,b=6