What is x^2-4y^2-16y>1 ?

The solution to x^2-4y^2-16y>1 is Hyperbola with (h,k)=(0,-2),a=(sqrt(15))/2 ,b=sqrt(15)

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x^2-4y^2-16y>1

x^{2} - 4 y^{2} - 16 y > 1

(h, k) = (0, - 2), a = \frac{15}{2}, b = 15

Solution steps

x^{2} - 4 y^{2} - 16 y > 1

Rewrite

x^{2} - 4 y^{2} - 16 y > 1

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{( \frac{15}{2} ) ^{2}} - \frac{( x - 0 ) ^{2}}{( 15 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 2), a = \frac{15}{2}, b = 15

25 x^{2} - 4 y^{2} + 40 y = 0

5 y^{2} - 4 x^{2} - 80 = 0

(u - 7)^{2} = 2 y^{2} - 18 y + 28

2 (x^{2} - 10 x) - 9 (y^{2} - 8 y) = - 16

\frac{x ^{2}}{36} - \frac{y ^{2}}{100} = 1

What is x^2-4y^2-16y>1 ?
The solution to x^2-4y^2-16y>1 is Hyperbola with (h,k)=(0,-2),a=(sqrt(15))/2 ,b=sqrt(15)