exzentrizität x^2+4y^2-2x-16y+13=0

Lösung

exzentrizität

x^{2} + 4 y^{2} - 2 x - 16 y + 13 = 0

\frac{3}{2}

Dezimale

0.86602 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

x^{2} + 4 y^{2} - 2 x - 16 y + 13 = 0 :

Ellipse with center

(h, k) = (1, 2), a = 2, b = 1

= \frac{2 ^{2} - 1 ^{2}}{2}

\frac{2 ^{2} - 1 ^{2}}{2} = \frac{3}{2}

= \frac{3}{2}

ecce n t r i c i t y \frac{( x - 1 ) ^{2}}{6} + \frac{( y - 3 ) ^{2}}{2} = 1

ecce n t r i c i t y \frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

ecce n t r i c i t y \frac{x ^{2}}{8} + \frac{y ^{2}}{3} = 1

ecce n t r i c i t y 10 x^{2} + 5 y^{2} = 50

ecce n t r i c i t y \frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1