What is the eccentricity (x^2)/(16)+(y^2)/(36)=1 ?

The eccentricity (x^2)/(16)+(y^2)/(36)=1 is (sqrt(5))/3

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eccentricity (x^2)/(16)+(y^2)/(36)=1

eccentricity

\frac{5}{3}

Decimal

0.74535 \dots

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 6, a = 4

= \frac{6 ^{2} - 4 ^{2}}{6}

\frac{6 ^{2} - 4 ^{2}}{6} = \frac{5}{3}

= \frac{5}{3}

What is the eccentricity (x^2)/(16)+(y^2)/(36)=1 ?
The eccentricity (x^2)/(16)+(y^2)/(36)=1 is (sqrt(5))/3