What is the eccentricity (x^2)/(36)+(y^2)/(16)=1 ?

The eccentricity (x^2)/(36)+(y^2)/(16)=1 is (sqrt(5))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity (x^2)/(36)+(y^2)/(16)=1

eccentricity

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

\frac{5}{3}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 6, b = 4

= \frac{6 ^{2} - 4 ^{2}}{6}

\frac{6 ^{2} - 4 ^{2}}{6} = \frac{5}{3}

= \frac{5}{3}

4 x^{2} + 9 y^{2} - 16 x + 18 y = 11

4 x^{2} + 3 y^{2} - 8 x + 18 y + 19 = 0

x^{2} + 4 y^{2} - 6 x + 20 y - 2 = 0

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

36 x^{2} + 9 y^{2} + 36 y - 288 = 0

What is the eccentricity (x^2)/(36)+(y^2)/(16)=1 ?
The eccentricity (x^2)/(36)+(y^2)/(16)=1 is (sqrt(5))/3