What is the foci (x^2)/(0.384^2)+(y^2)/(0.3758^2)=1 ?

The foci (x^2)/(0.384^2)+(y^2)/(0.3758^2)=1 is (0.07893…,0),(-0.07893…,0)

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foci (x^2)/(0.384^2)+(y^2)/(0.3758^2)=1

foci

(0.07893 \dots, 0), (- 0.07893 \dots, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{0.38 4 ^{2}} + \frac{y ^{2}}{0.375 8 ^{2}} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 0.384, b = 0.3758

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 0.38 4^{2} - 0.375 8^{2} : 0.07893 \dots

(0 + 0.07893 \dots, 0), (0 - 0.07893 \dots, 0)

Refine

(0.07893 \dots, 0), (- 0.07893 \dots, 0)

What is the foci (x^2)/(0.384^2)+(y^2)/(0.3758^2)=1 ?
The foci (x^2)/(0.384^2)+(y^2)/(0.3758^2)=1 is (0.07893…,0),(-0.07893…,0)