What is the foci (x^2)/(8^2)+(y^2)/(9^2)=1 ?

The foci (x^2)/(8^2)+(y^2)/(9^2)=1 is (0,sqrt(17)),(0,-sqrt(17))

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foci (x^2)/(8^2)+(y^2)/(9^2)=1

foci

(0, 17), (0, - 17)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{9 ^{2}} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 9, a = 8

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 9^{2} - 8^{2} : 17

(0, 0 + 17), (0, 0 - 17)

Refine

(0, 17), (0, - 17)

What is the foci (x^2)/(8^2)+(y^2)/(9^2)=1 ?
The foci (x^2)/(8^2)+(y^2)/(9^2)=1 is (0,sqrt(17)),(0,-sqrt(17))