What is the foci (x^2)/(4^2)+(y^2)/(3^2)=1 ?

The foci (x^2)/(4^2)+(y^2)/(3^2)=1 is (sqrt(7),0),(-sqrt(7),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

foci (x^2)/(4^2)+(y^2)/(3^2)=1

foci

(7, 0), (- 7, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 4^{2} - 3^{2} : 7

(0 + 7, 0), (0 - 7, 0)

Refine

(7, 0), (- 7, 0)

What is the foci (x^2)/(4^2)+(y^2)/(3^2)=1 ?
The foci (x^2)/(4^2)+(y^2)/(3^2)=1 is (sqrt(7),0),(-sqrt(7),0)