What is the foci 9x^2+25y^2+90x=0 ?

The foci 9x^2+25y^2+90x=0 is (-1,0),(-9,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

foci 9x^2+25y^2+90x=0

foci

(- 1, 0), (- 9, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 25 y^{2} + 90 x = 0 :

Ellipse with center

(h, k) = (- 5, 0), a = 5, b = 3

(- 5 + c, 0), (- 5 - c, 0)

Compute

c :

c = 5^{2} - 3^{2} : 4

(- 5 + 4, 0), (- 5 - 4, 0)

Refine

(- 1, 0), (- 9, 0)