What is the foci ((x-1)^2)/9+(y^2)/4 =1 ?

The foci ((x-1)^2)/9+(y^2)/4 =1 is (1+sqrt(5),0),(1-sqrt(5),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

foci ((x-1)^2)/9+(y^2)/4 =1

foci

(1 + 5, 0), (1 - 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x - 1 ) ^{2}}{9} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (1, 0), a = 3, b = 2

(1 + c, 0), (1 - c, 0)

Compute

c :

c = 3^{2} - 2^{2} : 5

(1 + 5, 0), (1 - 5, 0)

What is the foci ((x-1)^2)/9+(y^2)/4 =1 ?
The foci ((x-1)^2)/9+(y^2)/4 =1 is (1+sqrt(5),0),(1-sqrt(5),0)