What is the vertices 2x^2+y^2=50 ?

The vertices 2x^2+y^2=50 is (0,5sqrt(2)),(0,-5sqrt(2))

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vertices 2x^2+y^2=50

vertices

(0, 52), (0, - 52)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

2 x^{2} + y^{2} = 50 :

Ellipse with center

(h, k) = (0, 0), b = 52, a = 5

(0, 0 + 52), (0, 0 - 52)

Refine

(0, 52), (0, - 52)

What is the vertices 2x^2+y^2=50 ?
The vertices 2x^2+y^2=50 is (0,5sqrt(2)),(0,-5sqrt(2))