What is the vertices (x^2)/(63500)+(y^2)/(50900)=1 ?

The vertices (x^2)/(63500)+(y^2)/(50900)=1 is (10sqrt(635),0),(-10sqrt(635),0)

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vertices (x^2)/(63500)+(y^2)/(50900)=1

vertices

(10635, 0), (- 10635, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10635, b = 10509

(0 + 10635, 0), (0 - 10635, 0)

Refine

(10635, 0), (- 10635, 0)

What is the vertices (x^2)/(63500)+(y^2)/(50900)=1 ?
The vertices (x^2)/(63500)+(y^2)/(50900)=1 is (10sqrt(635),0),(-10sqrt(635),0)