{
"query": {
"display": "$$x^{2}+y^{2}+2x+6y+2=0$$",
"symbolab_question": "CONIC#x^{2}+y^{2}+2x+6y+2=0"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Circle",
"subTopic": "formula",
"default": "(a,b)=(-1,-3),r=2\\sqrt{2}"
},
"steps": {
"type": "interim",
"title": "$$x^{2}+y^{2}+2x+6y+2=0:\\quad$$Circle with center at $$\\left(-1,\\:-3\\right)\\:$$and radius $$r=2\\sqrt{2}$$",
"input": "x^{2}+y^{2}+2x+6y+2=0",
"steps": [
{
"type": "definition",
"title": "Circle Equation",
"text": "$$\\left(x−a\\right)^2+\\left(y−b\\right)^2=r^2\\:\\:$$is the circle equation with a radius r, centered at $$\\left(a,\\:b\\right)$$"
},
{
"type": "interim",
"title": "Rewrite $$x^{2}+y^{2}+2x+6y+2=0\\:$$in the form of the standard circle equation",
"input": "x^{2}+y^{2}+2x+6y+2=0",
"steps": [
{
"type": "step",
"primary": "Move the loose number to the right side",
"result": "x^{2}+2x+y^{2}+6y=-2"
},
{
"type": "step",
"primary": "Group x-variables and y-variables together",
"result": "\\left(x^{2}+2x\\right)+\\left(y^{2}+6y\\right)=-2"
},
{
"type": "step",
"primary": "Convert $$x\\:$$to square form",
"result": "\\left(x^{2}+2x+1\\right)+\\left(y^{2}+6y\\right)=-2+1"
},
{
"type": "step",
"primary": "Convert to square form",
"result": "\\left(x+1\\right)^{2}+\\left(y^{2}+6y\\right)=-2+1"
},
{
"type": "step",
"primary": "Convert $$y\\:$$to square form",
"result": "\\left(x+1\\right)^{2}+\\left(y^{2}+6y+9\\right)=-2+1+9"
},
{
"type": "step",
"primary": "Convert to square form",
"result": "\\left(x+1\\right)^{2}+\\left(y+3\\right)^{2}=-2+1+9"
},
{
"type": "step",
"primary": "Refine $$-2+1+9$$",
"result": "\\left(x+1\\right)^{2}+\\left(y+3\\right)^{2}=8"
},
{
"type": "step",
"primary": "Rewrite in standard form",
"result": "\\left(x-\\left(-1\\right)\\right)^{2}+\\left(y-\\left(-3\\right)\\right)^{2}=\\left(2\\sqrt{2}\\right)^{2}"
}
],
"meta": {
"interimType": "Circle Canonical Format 1Eq"
}
},
{
"type": "step",
"result": "\\left(x-\\left(-1\\right)\\right)^{2}+\\left(y-\\left(-3\\right)\\right)^{2}=\\left(2\\sqrt{2}\\right)^{2}"
},
{
"type": "step",
"primary": "Therefore the circle properties are:",
"result": "\\left(a,\\:b\\right)=\\left(-1,\\:-3\\right),\\:r=2\\sqrt{2}"
}
],
"meta": {
"solvingClass": "Circle"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\sqrt{(2\\sqrt{2})^{2}-(x+1)^{2}}-3",
"displayFormula": "(x-(-1))^{2}+(y-(-3))^{2}=(2\\sqrt{2})^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=-\\sqrt{(2\\sqrt{2})^{2}-(x+1)^{2}}-3",
"displayFormula": "(x-(-1))^{2}+(y-(-3))^{2}=(2\\sqrt{2})^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(-1,-3)"
],
"pointsDecimal": [
{
"fst": -1,
"snd": -3
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{Center}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"linesToDraw": [
{
"p1x": "-1",
"p1y": "-3",
"p2x": "1",
"p2y": "-1",
"attributes": {
"color": "GRAY",
"lineType": "BOLD",
"labels": [
"\\mathrm{radius=}2\\sqrt{2}"
],
"isAsymptote": false
}
}
],
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "(x-(-1))^{2}+(y-(-3))^{2}=(2\\sqrt{2})^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -7.3639610306789285,
"xMax": 5.3639610306789285,
"yMin": -8.821452268073777,
"yMax": 3.9064697932840775
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
Graph
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Frequently Asked Questions (FAQ)
What is x^2+y^2+2x+6y+2=0 ?
The solution to x^2+y^2+2x+6y+2=0 is Circle with (a,b)=(-1,-3),r=2sqrt(2)