{
"query": {
"display": "$$x=3y^{2}$$",
"symbolab_question": "CONIC#x=3y^{2}"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "formula",
"default": "(h,k)=(0,0),p=\\frac{1}{12}"
},
"steps": {
"type": "interim",
"title": "$$x=3y^{2}:\\quad$$Parabola with vertex at $$\\left(h,\\:k\\right)=\\left(0,\\:0\\right),\\:$$and focal length $$|p|=\\frac{1}{12}$$",
"input": "x=3y^{2}",
"steps": [
{
"type": "definition",
"title": "Parabola standard equation",
"text": "$$4p\\left(x-h\\right)=\\left(y-k\\right)^{2}\\:$$ is the standard equation for a right-left facing parabola with vertex at $$\\left(h,\\:k\\right),\\:$$<br/>and a focal length $$|p|$$"
},
{
"type": "interim",
"title": "Rewrite $$x=3y^{2}\\:$$in the standard form:$${\\quad}4\\cdot\\:\\frac{1}{12}\\left(x-0\\right)=\\left(y-0\\right)^{2}$$",
"input": "x=3y^{2}",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$3$$",
"result": "\\frac{x}{3}=\\frac{3y^{2}}{3}"
},
{
"type": "step",
"primary": "Simplify",
"result": "\\frac{x}{3}=y^{2}"
},
{
"type": "step",
"primary": "Factor $$4$$",
"result": "4\\cdot\\:\\frac{\\frac{1}{3}}{4}x=y^{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "4\\cdot\\:\\frac{1}{12}x=y^{2}"
},
{
"type": "step",
"primary": "Rewrite as",
"result": "4\\cdot\\:\\frac{1}{12}\\left(x-0\\right)=\\left(y-0\\right)^{2}"
}
],
"meta": {
"interimType": "Parabola Canonical Format Title 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7XyLbZXp+Wbh+m4tF03n6J+ICgXJ4Cd9yRyqYlJnfcIPsP/qQDlxeeNYW1ZWJxYAcfPwccPk04ro5gYDy4dxVexA0wxnGmkHWdrtVslPpf+0Q9qdJcuJZcQHTduTfqiU/aMukGpvKVutL4X5j8dyfMEBKzNvThwZxIgCl2Yl3fvOrve3E7cDlwD8G9VYfu6duRIMBF+ohPGZDN/D3oSP19IE5KqSizxQcz0mXfJLnLF/KSq/BachEG89jYXgLuVVqJLd1ohke2Wgml78++2zI0g=="
}
},
{
"type": "step",
"primary": "Therefore parabola properties are:",
"result": "\\left(h,\\:k\\right)=\\left(0,\\:0\\right),\\:p=\\frac{1}{12}"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\sqrt{4\\frac{1}{12}x}+0",
"displayFormula": "4\\frac{1}{12}x=y^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=-\\sqrt{4\\frac{1}{12}x}+0",
"displayFormula": "4\\frac{1}{12}x=y^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "x=-\\frac{1}{12}",
"displayFormula": "x=-\\frac{1}{12}",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(0,0)",
"(\\frac{1}{12},0)"
],
"pointsDecimal": [
{
"fst": 0,
"snd": 0
},
{
"fst": 0.08333333333333333,
"snd": 0
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4\\cdot \\frac{1}{12}(x)=y^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -0.9375,
"xMax": 0.9375,
"yMin": -0.9375,
"yMax": 0.9375
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the standard form:
Therefore parabola properties are:
Graph
Popular Examples
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Frequently Asked Questions (FAQ)
What is x=3y^2 ?
The solution to x=3y^2 is Parabola with (h,k)=(0,0),p= 1/12