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Popular >

foci y^2=-2x

Solution

foci

y^{2} = - 2 x

Solution

(- \frac{1}{2}, 0)

Solution steps

Rewrite

y^{2} = - 2 x

in the standard form:

4 (- \frac{1}{2}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{2}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- \frac{1}{2}), 0)

Refine

(- \frac{1}{2}, 0)

Popular Examples

x^2+y^2-4x+10y+13=0

x^{2} + y^{2} - 4 x + 10 y + 13 = 0

x^2+y^2+2x+6y+2=0

x^{2} + y^{2} + 2 x + 6 y + 2 = 0

asymptotes of (y^2)/9-(x^2)/(16)=1 asymptotes

\frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1

x = 3 y^{2}

vertices 3y^2=24x vertices

3 y^{2} = 24 x

Frequently Asked Questions (FAQ)

What is the foci y^2=-2x ?
The foci y^2=-2x is (-1/2 ,0)