What is (x^2)/(81)+(y^2)/(36)=1 ?

The solution to (x^2)/(81)+(y^2)/(36)=1 is Ellipse with (h,k)=(0,0),a=9,b=6

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(x^2)/(81)+(y^2)/(36)=1

\frac{x ^{2}}{81} + \frac{y ^{2}}{36} = 1

(h, k) = (0, 0), a = 9, b = 6

Solution steps

\frac{x ^{2}}{81} + \frac{y ^{2}}{36} = 1

Rewrite

\frac{x ^{2}}{81} + \frac{y ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{9 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 9, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 9, b = 6

x^{2} + 25 y^{2} - 200 y + 375 = 0

\frac{( x + 1 ) ^{2}}{36} + \frac{( y + 3 ) ^{2}}{25} = 1

x^{2} + 9 y^{2} + 2 x - 18 y + 1 = 0

\frac{x ^{2}}{4} + \frac{( y - 1 ) ^{2}}{9} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{80} = 1

What is (x^2)/(81)+(y^2)/(36)=1 ?
The solution to (x^2)/(81)+(y^2)/(36)=1 is Ellipse with (h,k)=(0,0),a=9,b=6