What is (x^2)/(16)+(y^2)/(80)=1 ?

The solution to (x^2)/(16)+(y^2)/(80)=1 is Ellipse with (h,k)=(0,0),a=4,b=4sqrt(5)

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(x^2)/(16)+(y^2)/(80)=1

\frac{x ^{2}}{16} + \frac{y ^{2}}{80} = 1

(h, k) = (0, 0), a = 4, b = 45

Solution steps

\frac{x ^{2}}{16} + \frac{y ^{2}}{80} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{80} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{( 4 5 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 45

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 45, a = 4

4 x^{2} + y^{2} - 16 x + 2 y + 1 = 0

\frac{( x - 3 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{36} = 1

2 x^{2} + y^{2} + 16 x - 4 y + 32 = 0

\frac{( x - 5 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{4} = 1

4 y^{2} - 338 x + 32 y = - 169 x^{2} + 443

What is (x^2)/(16)+(y^2)/(80)=1 ?
The solution to (x^2)/(16)+(y^2)/(80)=1 is Ellipse with (h,k)=(0,0),a=4,b=4sqrt(5)